math:trigonometry
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| - | WIP | + | # Generalized Pythagorean Equation |
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| + | given: triangle with an angle **C** with adjacent sides **a** and **b** and opposite side **c**. | ||
| + | |||
| + | * bisect **b** (or **a**) at right angle with line passing thru opposite angle | ||
| + | * works easier with obtuse angles such that intersection is internal to triangle - otherwise you end up hanging on the outside of the triangle which feels awkward. | ||
| + | * we choose to bisect a side other than **c** so we don't bisect angle **C** | ||
| + | * label this new line **x** and the divided parts of **b** as **y** and **z** | ||
| + | * **y** + **z** = **b** | ||
| + | * from basic Pythagorean we can state the following: | ||
| + | * x< | ||
| + | * x< | ||
| + | * we can eliminate x< | ||
| + | * x< | ||
| + | * isolating c< | ||
| + | * c< | ||
| + | * removing one of the parts of b (since y + z = b then z = b - y) | ||
| + | * c< | ||
| + | * expanding (b - y)< | ||
| + | * c< | ||
| + | * remove the y^2s | ||
| + | * c< | ||
| + | * from SOH-CAH-TOA we can state that | ||
| + | * cos(C) = y/a | ||
| + | * y = a * cos(C) | ||
| + | * substitute for y | ||
| + | * c< | ||
math/trigonometry.1764620846.txt.gz · Last modified: 2025/12/01 20:27 by ron
